Assessment & Testing· Measurement Foundations

Norms & standardized scores

High-yieldCovers z-scores, T-scores, stanines, percentiles, normal curve landmarks.

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Study summary

A raw score of 42 tells you nothing. Forty-two out of what? Compared to whom? Standardized scores solve this by locating a person on the normal curve relative to a norm group — and the exam demands you convert between them fluently, because the whole family is just the same bell curve wearing different clothes.

Start with the normal curve and its landmarks: it's symmetric, and the 68-95-99.7 rule says about 68% of scores fall within ±1 SD of the mean, 95% within ±2 SD, and 99.7% within ±3 SD. Every standardized score is anchored to this curve.

The z-score is the mother score: mean 0, SD 1. A z of +1 means one SD above the mean. Because z-scores carry decimals and negatives, we rescale them. The T-score has mean 50, SD 10, computed as T = 50 + 10z — so z=0 is T=50, z=+1 is T=60 (used on the MMPI and many clinical inventories). Stanines ('standard nines') compress scores into 1-9 with a mean of 5 and SD of 2. Percentile ranks tell you the percent of the norm group scoring at or below a person — the 50th percentile is the median, and it lines up with z=0 and T=50. The deviation IQ uses mean 100, SD 15.

The anchor points to burn in: z = 0 = T-score 50 = 50th percentile = stanine 5 = IQ 100 — all the dead center of the same curve. One caution: percentiles are not equal-interval, so they bunch up in the middle and stretch out at the tails.

Clinical Pearl: Memorize the center-line conversion — z=0, T=50, 50th percentile, stanine 5, IQ 100 all mark the exact same point — and remember T = 50 + 10z lets you jump from any z straight to a T-score.

Cheat sheet

NCE · Assessment & Testing

Norms & standardized scores

A percentile rank is the percent of the norm group scoring at or below a person; the 50th percentile is the median.

01 · The conceptNormal curve: 68-95-99.7 rule
02 · Must knowz-score: mean 0, SD 1
03 · Must knowT-score: mean 50, SD 10
01

Key terms

Raw score needs a norm groupA raw score alone tells you nothing; standardized scores locate a person on the normal curve relative to a norm group.
02

Statistics concepts

Normal curve: 68-95-99.7 rule must knowThe normal curve is symmetric, and the 68-95-99.7 rule says about 68% of scores fall within +/-1 SD of the mean, 95% within +/-2 SD, and 99.7% within +/-3 SD.
z-score: mean 0, SD 1 must knowThe z-score is the base standard score with mean 0 and SD 1; a z of +1 is one SD above the mean.
T-score: mean 50, SD 10 must knowThe T-score has mean 50 and SD 10, computed as T = 50 + 10z, so z = 0 is T = 50 and z = +1 is T = 60; T-scores are used on the MMPI and many clinical inventories.
Stanine: 1-9, mean 5, SD 2 must knowStanines ('standard nines') compress scores into 1-9 with a mean of 5 and an SD of 2.
Deviation IQ: mean 100, SD 15The deviation IQ is one more standard-score family, with mean 100 and SD 15.
Center line: z0, T50, IQ100z = 0, T-score 50, the 50th percentile (median), stanine 5, and deviation IQ 100 all mark the exact same center point of the normal curve.
Score conversions at each SDOn the same curve: z = -1 -> T 40, ~16th percentile, stanine 3, IQ 85; z = +1 -> T 60, ~84th, stanine 7, IQ 115; z = -2 -> T 30, ~2nd, stanine 1, IQ 70; z = +2 -> T 70, ~98th, stanine 9, IQ 130; z = -3 -> T 20, ~0.1, stanine 1, IQ 55; z = +3 -> T 80, ~99.9, stanine 9, IQ 145.
Percentiles are NOT equal-interval: they bunch up in the middle of the distribution and stretch out at the tails.
03

z-score vs T-score

Commonly confused
z-scoreT-score
Mean050
SD110
One SD above the meanz = +1T = 60
ConversionBase scoreT = 50 + 10z
04

More detail

Show 1 reference fact
Why z-scores get rescaledBecause z-scores carry decimals and negatives, they are rescaled into families such as T-scores and stanines.
Pearl

z = 0, T = 50, the 50th percentile, stanine 5 and IQ 100 all mark the same point, and T = 50 + 10z gets you from any z to a T.

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A counselor reads that a client's z-score on a coping inventory is +1. Where does that place the client relative to the norm group?

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